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[打法交流]
分享3d杀尾秘籍 助您轻松预测和值(一)(转)
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分享3d杀尾秘籍 助您轻松预测和值0 K5 V. k1 e( |0 I2 }
(一)0位遗漏排除和尾
0 Y% o+ w* C; t* x5 E在和尾0到9的分布图上,我们把每期0位出现的不管它出现的是0的和数值以及它的遗漏期,我们把这个期数的尾数加上1,那么就是下一期可以排除的和值尾。
$ [! {+ W, b* Z( N1 p+ A(二)和数排除和尾
: J' \/ [& b/ u) n5 V4 C, Z' x/ m我们所说的和数指的是和值,和值一共有28个,也就是说从0、1、2、3、4、5、6、7、8、9一直到27这个和值,按照这个顺序,我们这样写下来。只有0和19,这是两个和值点对着的,其余的我们竖着列起来都是三个为一组。3点、12点、21点都是这样竖着,我们把竖着的一列作为一组。当出现的和值,它出现在哪个位置上的时候,我们就可以把这一列的和值点都排除掉,同时,我们还可以看它左斜线的和值,这样又可以排除掉两个和值,这个方法准确率相对很高。
+ ` _5 J4 Y3 f. R0 O. j2 N6 ^4 U% I(三)跨差排除和尾( i# J' o; {1 _9 L! x6 n7 t! D# w
跨差排除和尾就是我们用上下两期奖号的跨度,相减出来的差,那么就是下一期可以排除的和值尾。
+ m: R @: m2 b, }' S; t(四)和值乘3加3排除和尾
v; Q+ m! R$ w; d5 `* u3 Z2 L我们把上一期奖号的和值乘3加3后,得到的数尾,那么就是下一期可以排除的和值。例如,某期开出的奖号是314,这是一个8点的和值,那么我们拿8乘3加3以后,得到的数就是27,我们取它的尾,就是尾7,那么尾7就是下一期可以排除的和值尾,尾7包括小7、17以及27点的和值# s1 h6 k& {' I0 ~' B/ F1 t
* O$ b' n4 C: u. j
(五)遗左乘遗右排除和尾8 ?5 Q H/ T3 S. x
上一期出现的和值尾,我们看它左边的遗漏期以及右边的遗漏期,把两个遗漏期的期尾相乘出来,这个尾数就是下一期我们可以排除的和值尾数。9 t3 G$ i$ j P; @8 q
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