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[打法交流]
近期在网上研究到了个百家乐著名战术 蒙特卡洛战术
[复制链接]
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百家乐蒙特卡洛战术，需要纸和笔。但是不很难。# s6 B# q$ w" p, b' K: {
1 l6 Q3 T N2 ?( q/ j(1) 首先写「 1 2 3 」的数列。# ?' D. H8 O/ E# \9 I% ?
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(2) 赌本就是左端的数字 (1) 加右端的数字 (3) 即是 (4) 。
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% c0 d# S, S/ d! l3 a(3) 输了的话就在数列右端之外又加上顺序的下一个数，现在这个例子要加的数字 (=4) ->( 「 1 2 34 」 ) 。如此类推，并且重複上面的第 (2) 点 ( 但今次会是 (1)+(4)=5) 。5 v) q7 D' S) }1 ~$ G
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(4) 胜了的话，倍率 2 倍的游戏就把左端的数字 (1) 和右端的数字 (3) 消去。倍率 3 倍的游戏从数列上去掉左端的二个数字和右端的二个数字。
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(5) 如果数列所有的数字都消了就代表结束。$ E0 q/ O! g7 ~' j
& S# W, w4 J0 d: s: x* [* m* j(6) 想继续的话，回到 (1) 。* H( P$ { F5 Z* D; X6 M5 L
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蒙特卡洛战术的问题，在于如果没有充分而源源不绝的赌金，就会出现途中被迫停止的可能。而且连败的话，亦有机会超越 Max Bet ( 赌注的上限额 ) 。4 {+ k2 z$ E* K1 {
?* d5 ]: J, A5 @% b3 _二合一战术0 r3 p9 O7 m/ Y9 e9 W5 J
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这个可说是蒙特卡洛战术的一种，是以 1 局取回 2 局所输的方法。方法简单。写下输了的金额，赌注就那个左端和右端的数字的共计金额。
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8 d# v+ W' L4 |- _8 M9 I譬如，先写下「 1 」。所以第一局的赌注是 1 。如这局输了，右侧添写 1 ，成为「 1 1 」。那个下一局赌注将会是左端和右端的共和 =2 。
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5 R% i+ Y( m, `" O反复这样做，如四连败，数列将成为「 1 1 2 3 」。因此下一赌注会是 4 ，而且胜了的话，消去左端和右端的数字，数列将成「 1 2 」，下一赌注就等于 1 和 2 的总数 3 。再胜的话，会变成？7 {+ P& Y: }0 Q1 r/ f2 x* W4 c
! Z' L7 b+ d- ~: y( _( \儘管结果是 2 胜 4 败，共计收支是一加一减等于零。
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) l7 K) a7 l6 s/ T8 p这方法我试了不咋地，你们可能可以?
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