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[lastpost] => 2775417 【星宝】10月21日投注流水166330元 1761119021 rainwang
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通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。
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9 }: Y. b! O( M5 S2 _- k0 ^ 假设大路开这样的路:, X) P( M& L$ L; Y* H: p
4 M1 C! d! x% `2 s
12121212121212121212121212121212。, `/ O# R. R# Q4 W) _6 x
( ]+ ^" s. `: `3 `& W5 U' O5 R
按2珠路,就是BPBPBPBPBP。
2 v" Z8 U0 e# L, N! Q' e- X" x4 ?. b$ r4 i6 E8 ^6 `" ^: l9 {
如果我们去掉第一口,就会出现完全相反的结果:( v* l4 |6 G& a3 Y" _( w; W
- y( K* P+ h0 W$ i3 d- ~% a! w: @ 21212121212121212121212121212121。; g2 y' i. }4 m, h+ O
# i! ~# x+ m/ O 变成了PBPBPBPBPB。
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9 L+ f& k' ?# D6 o6 S* [ 如果我们再去掉一口,又返回第一种情况了。8 [1 E3 R2 |8 [0 |
' o$ B" [% q0 x 所以每一条大路,按2珠路排列,有2种不同的路数。0 @, f$ y3 h( ^. X2 n% T
+ T2 H2 C* J7 Z' R+ { 再举一个列子:& N) |; @) a* S$ `" ~! G
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大路:122122122122122122。
: t- x4 T: Z! B
* Z, w( H% M7 j( B7 i0 [! T. g7 Q8 f 按三珠路排列:" R- Z9 U6 g' p1 q
- G P* ?4 @6 ^- ]+ k/ T4 c" h 122,122,122,122,122,122。
6 s X1 ]/ a6 n6 C7 ^6 N8 S) C e" `9 k* D/ l2 Q2 v
去掉第一口,变成:
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221,221,221,221,221,去掉前2口,变成:
V/ S* E( n+ n
5 V; _6 l3 B2 e: e' } 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。
, D+ h+ u2 K& k4 z% Q) X7 ]6 r8 G- M/ d- h: n0 W& Y
同理:按N珠路排列,有N种不同的路数。1 X1 I" z& v3 W+ p% D
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我提出这个的意义在于:
7 e/ J5 ^5 S/ m: ]+ |: p7 x) F# F3 i7 u% d8 V2 F
1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。9 A3 J1 k' }' U& x& o5 p; U
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2、为三多理论提供了下注的多面性奠定基础。
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# F" X/ l$ {& @8 ?" J% e 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。
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我现在还是研究一下理论打法,感谢你的分享,我也来学习 |
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