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根据技术型彩民多年研究，得出以下几步大乐透的破解方法： , w+ B) n$ Y6 b( [- ]9 x! |% |$ `
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第一，前区号码初步判断，确定冷热号 & k! n3 T: m; `
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根据前2-3期开出的号码，确定热号和冷号。比如前三期分别开出的号码为： : p( e5 C$ V4 e' R$ N* e [4 n
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11 12 14 24 29 + 05 07 " g" W- M6 U7 ~; w' J/ n3 Z9 N c
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10 12 20 21 25 + 06 09 01
' Z0 D" ~8 R( O( v! d, ~) L- _3 T* \" ]
0 Z) V' ?. u4 T) d0 F) C0 [$ H 12 23 28 35 + 02 05
7 f) B) |' X: c$ _; c( l: C+ G8 I
! u: c. L& Y) i2 z) D: x 我们可以看出12是最热号，3次都开出,01是最冷号，开出1次，而且没有周边号码（02、 03）开出。一般热好至少5期内容易继续开出，而且大乐透喜欢开出同尾的号码（比如12-22- 32）
- q& n8 T& h( U# E/ d, d
# `9 Y( f% i6 D( A$ T 第二，初步杀出前区号码 - A4 P z9 [0 p' u2 a. @7 X% }. |- f' l1 I
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一般前1期的号码可以作为杀号的最好依据。我们可以认为只有1-2个号可能继续开出，所以 可以大胆杀掉3个号码。杀号可参考0 1 2路来进行判断，0路是指除3余0号码，1路则是除3余1,2 路除3余2。- C! H8 S8 z% X" U, }+ f
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可见 1（1路） 12 （2路）23 （0路）28 （2路）35（2路） + 2 5
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其中 2路号最多，可以杀掉1个，因此杀掉 35，（上期杀热号）。
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0 b6 n2 c( r- W9 u 0路号这3期中比较冷，也可杀掉，因此杀掉 1，23（连3期杀冷号）。
2 l' ?4 w5 X k' ^' t! G! x# m7 s+ t( G }; R$ K6 G8 m$ `
以此类推，我们可以去掉1、23、35的1-35个号码中随机抽取4个（按照210路比例为1： 1:2）（杀掉的0路号最多，所以在比例上，0路号多一个）2 I5 h2 y# r Z# U/ s9 l. r
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比如 选取 “8”“17”“19”“30”（过程中奇数偶数比例最好设为2:2）) ^" S0 _ K+ r2 Y8 J
3 {# m2 k! x. x5 l: Y9 o* _; e
第三，确定前区号: Z* g/ q8 X1 \, ]. C
) k1 H/ t8 e+ s, D0 {& k$ a 综合前两点，前区选号为 08 12 17 19 22 30，此时依据奇数偶数比例，随机杀掉一个（上 期的奇数偶数比是3:2），这次我们可以选择比例为2:3（倒置） ，所以杀掉一个奇数17，因此得 出前区最早选号为 8 12 19 22 30。
$ p' d- N; ^: P/ |0 V
) {" \! m' l$ | 以上三步确定红球方法，不止个位掌握与否4 V; e ^" J" ]% \: }
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