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一、百家樂常见的错误
% s! u. Y/ ~$ }5 H- E" I3 ?) h- A' U3 c+ z
3的搭配机率是1/8，如果见持续3个不异的搭配，例如BBPBBPBBP之后用3式缆反买BBP（即PPB），中一口的成功机率是否1/8x/1/8x1/8x1/8=1/4096答案是否认的。由于持续3个不异搭配已经实际呈现，等于4096个搭配之中有4096–8=4088个搭配不成能呈现，只剩低余下的8个搭配可以呈现，所以胜的机遇率仍旧是7/8。现详细列出他们以便利理解：
0 I6 g+ Z& l0 d) p; U$ [
7 M3 _* y: N5 k1、BBP，BBP，BBP，BBB# _. v; B# c9 s g( [% @
2、BBP，BBP，BBP，BBP( [. r3 m3 l7 } `& @8 X8 C5 m
3、BBP，BBP，BBP，BPB
. q: D, m8 \7 T3 g! _' u4、BBP，BBP，BBP，BPP8 {9 u9 b$ n* G7 x+ h
5、BBP，BBP，BBP，PPP( W. T- M6 {7 I- Q( @
6、BBP，BBP，BBP，PPB
% h2 I4 B0 R1 i- y. r7、BBP，BBP，BBP，PBP: _, r5 U3 ~/ d. `5 U- |% R
8、BBP，BBP，BBP，PBB% g' o0 i+ L" p- i
/ r5 Z3 z% E! I0 T) c2 Y% k
所以无论是什么搭配，当它已经实际呈现，它的概率必定是1。已经实际呈现的BBPBBPBBP概率是1，用3式缆买反的整体胜率依然是7/8。. ~. |4 K! z* l* p
2 Y4 _ U. v4 k) u1 a
二、2式缆赌N搭配的错误有一个很自然的想法，之前开了例如BBBPB，跟着反买它即PPPBP去赢1个码,机遇率是1/32，死穴是反复的BBBPB。7 Z7 V+ n+ J# V5 S! W% K9 ]
+ z& l4 E. t2 ^$ m7 b4 I0 B: @为了节流金钱，好自然想到如果输了1口或2口才追，一来可以增加取胜机遇，二来可以节流金钱，所以便发生“同买分歧，分歧买同”的心理和策略。例如:见BBBPB，再见B，可能会认为如果买了第一口已经输了，余下四口用4式缆博赢一口的机遇会大一些；又或者等已出了二口BB才用3式缆博赢一口的机遇会大一些。现实上，这个策略是按比例裁减了一些胜及负的搭配来换取低成本:只见B才下注，便会错过8个BXXXX及8个PXXXX的搭配；同样只见BB才下注，便会错过12个BBXXX及12个PPXXX的搭配；所以这个策略亦没有提高风险回报比率，它的取胜机率完全由运用的式缆来决议，即2式缆=3/43式缆=7/84式缆=15/16。" x7 `# N4 E8 z2 v; M
三、结论# v. w" W, I4 S( n
+ ` V6 O& E) Q9 {, u$ F无论等任何模式下注，如，PP后买B（拐弯法）；PPBP后买P连；PPBPPPBP后买P不连完全没有影响50%定理。! S) w8 F Q* u+ X4 U6 K) f
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