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通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。 f+ W' q l& p6 B+ g) A" ]
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假设大路开这样的路:" \: Q h& S. T6 y1 ^' ~5 y
K2 @ d' p2 `8 {$ M
12121212121212121212121212121212。
& g) q- U% I, F% X) U& e7 m* N5 q& ?3 [, Y3 L
按2珠路,就是BPBPBPBPBP。; M9 E$ ~2 T* W
2 Q9 {/ x& e7 ^, F
如果我们去掉第一口,就会出现完全相反的结果:
8 x. C8 J7 |9 f3 r$ B. z7 c( V, n$ E' b& T2 z& R
21212121212121212121212121212121。: K* d$ {) c; @+ \1 h A
' C: O/ n* P" e1 V! g" K9 ]* j
变成了PBPBPBPBPB。- ]% b m! q- w0 f
5 H/ D: p; o' j7 E* ~+ p
如果我们再去掉一口,又返回第一种情况了。
/ Z; d( k, Q2 A N% i
& B. R T: b/ u% k1 | u 所以每一条大路,按2珠路排列,有2种不同的路数。
' Y( c) D8 e9 h7 E- a+ s) s F( u( u9 t8 X. D; y7 B- l" h! ?' G
再举一个列子:; i7 v/ [9 `! ~+ {0 P7 V( \
1 B+ x+ G! a+ ~9 ^ 大路:122122122122122122。5 B) X' @7 n2 g7 u5 c: u
R% I2 O6 K4 b4 j7 R; d! Q# Z* |& P
按三珠路排列:
2 x0 e- _% v2 @2 [- \
& n: G1 h5 g5 S2 v' [+ }5 V 122,122,122,122,122,122。) }" U% o3 O. g* n9 u& ^; R( Y
3 M0 S" z$ Z$ ]# Z/ Q 去掉第一口,变成:
. j1 W$ R+ e4 a$ O7 ?6 r& L' X, i/ Z( P0 M4 Q0 w: n1 B+ i
221,221,221,221,221,去掉前2口,变成:# B4 o5 l, }/ K! D
. P! D/ J" ~& Y; L9 G. K 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。
" m# g. n% M9 i9 r* m) u0 i; z4 g* |$ z$ P
同理:按N珠路排列,有N种不同的路数。
Z T5 D& x) a# w) E: J7 ]% s' W# ~2 [" ~5 s% C$ t
我提出这个的意义在于:
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1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。; K. M0 z7 ]; x, {7 B
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2、为三多理论提供了下注的多面性奠定基础。2 i* R1 v0 {5 @9 q
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3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。
& M4 i* Q7 _2 |. v6 N+ Y6 A$ G3 i: t8 S" p. F' d2 E
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我现在还是研究一下理论打法,感谢你的分享,我也来学习 |
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