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通过我几个月来对珠路理论的研究,
' W+ Q) J# [- k+ ]* k+ l
e: J2 S6 o1 V$ l! R0 I" S7 I发现了一个有趣的现象,# A& ?2 C" ]4 Q0 D
每一条大路,& I: T! [: |) X7 z
按2珠路排列,有2种不同的路数
# C" |- J" O1 ]0 d- ^) a按3主路排列,有3种不同的路数6 U" o& M5 c/ F% [, o6 L
按4珠路排列,有4种不同的路数 y! J3 C* N+ W: y
按N珠路排列,有N种不同的路数。- K: w2 Z9 }( L5 s& l- i
什么意思呢,可能大家一时不清楚,
- |4 R8 P( T, U# |1 ]我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。; Q& i+ {: ]# u
假设大路开这样的路:
5 W1 \0 Y5 v' j6 Z' ^6 K4 w+ S12121212121212121212121212121212
8 ~% i" v! m2 b& j; K够极端了吧
( _# b( z2 D/ `. i9 A- _5 l按2珠路,就是BPBPBPBPBP.....
" C4 A g* v0 t5 H如果我们去掉第一口,就会出现完全相反的结果:
7 c5 u$ D! v. A8 m. R) t5 v9 X21212121212121212121212121212121
3 z& x# k6 ?- g1 M7 T. H变成了PBPBPBPBPB.......
2 g) Z8 w& R1 ?9 ^2 u8 A% U. w如果我们再去掉一口,又返回第一种情况了。
( F+ l9 k# S+ I1 s6 L4 ~* K所以每一条大路,/ @+ z8 G/ {' V3 C! G0 W7 r
按2珠路排列,有2种不同的路数。4 P. A( ~: ~5 Y3 c% T1 t1 ^# x
再举一个列子:
! e# |, m! B1 M& o& y. `. d3 C' ^大路:122122122122122122。。。 w. M( e5 b; S1 n- Y8 ~- G
按三珠路排列:
J& |+ g9 z. W122,122,122,122,122,122。。。
+ \/ ~' e6 B/ o2 c& S5 ]! Z去掉第一口,变成:
! P6 k, U7 O! H' x3 a. `1 w1 A0 A221,221,221,221,221,6 u% c" P/ l' s; k% ^* w2 V- w
去掉前2口,变成:
# Z/ r; Z) R/ K212,212,212,212,212,1 w8 r$ ^2 |* L' B
去掉3口,又返回122,122,122,了
/ ^+ I) O! a% u9 A. q/ q- |5 A9 f所以每一条大路,
/ N' `) r( D c _( m按3珠路排列,有3种不同的路数。* f" \2 }" ]7 Z$ n3 S/ W" X6 O
同理:按N珠路排列,有N种不同的路数。0 _( P! [; W* U6 k {, b
我提出这个的意义在于:
: n6 S4 Q3 P( H: P, S字串8* h9 q+ C0 i5 I2 ] e7 w4 e
! Y7 Y `: o; o2 f2 E! ]+ G1、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
! B) r: e9 m9 Y4 ~* z2、为三多理论提供了下注的多面性奠定基础。
1 `7 _! \! x8 x3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是 上上路.
6 q5 y$ P9 l4 W! P$ g' Z# V |
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你的理论打法不错的呀,赢钱了应该是打法对你有用哦~来收藏下了解下了 |
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我现在还是研究一下理论打法,感激楼主的分享,我也来学习 |
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楼主估计也是一个理论很内行的玩家,谢谢老哥的分享。 |
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