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以下是输给那破游戏不甘心后的乱想..如有错误请提出或无视.. 首先是豹子问题- h% B7 Y0 y* b& r2 ~. c" L7 c
1 Y2 q/ j6 [8 O7 }/ Q0 w因为太郁闷..所以从排列组合开始..
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8 H8 x% u: r( h5 L! x假设直线A上有N个点，取任意点都有相同程度的概率.那么有2个取点者同时随即取点E，2者同时取得点E的概率是E/N*N
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9 O( }- [ b( j$ t# g+ c" Y" t那么豹子的出现概率是2/216=0.00926=0.926%
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豹子的赔率是30那么收益期望为0.2778风险为99.074%
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连续2次出现率为42.67%的负4次方（大概是大型超市抽奖活动的特等奖的概率..有信心的可以玩下）6 f; ~; I9 d4 U
/ ^* E3 M4 T2 d* ]2 w9 _5 X1 k在是压大小问题./ ~9 @4 _; X( S2 r; l5 D% J* D
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根据以上得出每组大小的概率是49%..& L4 G5 V" u! [* D3 c3 ]
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由此可见..压大小就总合来说是必败的4 x" p' [0 X ]2 q) V
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心理学中有个叫赌徒效应还是啥啥的..是说随即序列发生一个事件的概率与之前发生的事件无关。即发生的概率并没有因先前发生的事件而增加。
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也就是说，压大小实际上永远就是49%概率压对。
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并非这次压错了.下次就是50%了* d& H4 N, l) g7 h* @2 M) P ^+ w
) O T: g' U+ g1 d由此可见压大小以综合来说必输.压豹子其收益价与风险值不成比列。
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根据以上分析.还是奉劝大家！远离DB！' o/ K- a! U3 S9 Z
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还有..以上是有实际验证的~昨天赌了上百回资金流动大概有成千上万..损失了进两百1 m3 s+ B# i2 }8 W& b$ V( F7 y
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今天中午又赌了N次..资金流动上千..损失了30左右..均与以上概率成比例~ 嘛- -偶赌的还算比较厉害了..输的惨就不去说了~~那位上千的全没了
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偶决定在也不赌了~真的...9 T0 Z' L$ a2 U1 H
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