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[打法交流]
近期在网上研究到了个百家乐著名战术 蒙特卡洛战术
[复制链接]
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百家乐蒙特卡洛战术,需要纸和笔。但是不很难。
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(1) 首先写「 1 2 3 」的数列。
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(2) 赌本就是左端的数字 (1) 加右端的数字 (3) 即是 (4) 。5 i( Y i! [9 V5 W+ e, [
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(3) 输了的话就在数列右端之外又加上顺序的下一个数,现在这个例子要加的数字 (=4) ->( 「 1 2 34 」 ) 。如此类推,并且重複上面的第 (2) 点 ( 但今次会是 (1)+(4)=5) 。
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(4) 胜了的话,倍率 2 倍的游戏就把左端的数字 (1) 和右端的数字 (3) 消去。倍率 3 倍的游戏从数列上去掉左端的二个数字和右端的二个数字。. K6 X$ j- \- w
* U+ r9 o( R# ~6 C$ l& N(5) 如果数列所有的数字都消了就代表结束。4 R/ N- ?0 H' X* A$ R
F7 J4 D6 C0 v$ R0 m1 W(6) 想继续的话,回到 (1) 。$ n) p3 r2 l# {. p V: X: }/ V& T* m
, p7 D0 F! `* H1 \蒙特卡洛战术的问题,在于如果没有充分而源源不绝的赌金,就会出现途中被迫停止的可能。而且连败的话,亦有机会超越 Max Bet ( 赌注的上限额 ) 。: x M' H, a2 n0 x o+ K# q: q0 Y- d
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二合一战术2 l& N& K9 g2 o4 U6 i% m
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这个可说是蒙特卡洛战术的一种,是以 1 局取回 2 局所输的方法。方法简单。写下输了的金额,赌注就那个左端和右端的数字的共计金额。2 ^4 D6 W' a( t
# k' H, n, [8 L3 [ u) ?: x& t. b譬如,先写下「 1 」。所以第一局的赌注是 1 。如这局输了,右侧添写 1 ,成为「 1 1 」。那个下一局赌注将会是左端和右端的共和 =2 。
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反复这样做,如四连败,数列将成为「 1 1 2 3 」。因此下一赌注会是 4 ,而且胜了的话,消去左端和右端的数字,数列将成「 1 2 」,下一赌注就等于 1 和 2 的总数 3 。再胜的话,会变成?
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儘管结果是 2 胜 4 败,共计收支是一加一减等于零。
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. h+ r- k3 a r. r3 z U5 D这方法我试了不咋地,你们可能可以?- B2 H' Z# B8 k5 t
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