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通过我几个月来对珠路理论的研究,
' j5 I: T8 K0 p& ~7 ]& K
9 x9 F8 Z( @) T) j' B' v% G发现了一个有趣的现象,
1 O- K4 P1 ^% P0 F7 P每一条大路,
( k s. N7 H% ^9 d, e按2珠路排列,有2种不同的路数
3 j' }9 }" ]/ g2 B+ [' {6 x按3主路排列,有3种不同的路数
5 r" f) a& m, g% n) T按4珠路排列,有4种不同的路数
- X( ^- q& Q, L; p按N珠路排列,有N种不同的路数。
# t7 P( k7 |. K6 X/ `- t" t什么意思呢,可能大家一时不清楚,6 l/ V% Z5 G7 Y2 |0 Y/ B9 D$ k
我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。# _9 J @* Q5 P
假设大路开这样的路:
0 U: c2 x$ I; h' o/ w( f7 x2 _- t2 R12121212121212121212121212121212
3 q: d! w3 g7 v$ H. A够极端了吧
/ |0 I+ l' m$ H m8 w按2珠路,就是BPBPBPBPBP.....
! l% z: X1 f$ k# x2 ~如果我们去掉第一口,就会出现完全相反的结果:) s0 ~, X( ~. m
21212121212121212121212121212121
+ o: y2 j4 y( M: A, e# q6 u' j变成了PBPBPBPBPB.......4 O( W: G; t4 Q1 V/ h( A+ y# t
如果我们再去掉一口,又返回第一种情况了。% g( L2 L, F( a- V; @$ H
所以每一条大路,( U8 Z- L( S0 F2 B6 T# R
按2珠路排列,有2种不同的路数。
0 [7 k# p9 n. ~; k6 \再举一个列子:+ v) k1 ?! n! J, n7 J( ?
大路:122122122122122122。。。8 D u4 x5 e* c/ R5 W
按三珠路排列:- m& w" G' x4 \( {4 S6 D1 z
122,122,122,122,122,122。。。; A+ u- \4 Y3 \4 H: N
去掉第一口,变成:
& G' [$ ]; U/ _221,221,221,221,221,
. g* y/ K- B1 |, _8 D* L去掉前2口,变成: h- |3 n4 }0 N7 A& Y/ Q
212,212,212,212,212,
- S* Y6 ~# k0 n0 W2 f去掉3口,又返回122,122,122,了) A& }( q- ]: P' ~% m$ K+ w
所以每一条大路,
8 s. T9 W- r- }8 ?8 r* b按3珠路排列,有3种不同的路数。" Q# [4 b r8 G/ }4 u s
同理:按N珠路排列,有N种不同的路数。: H0 d; J" Q `, y
我提出这个的意义在于:
; G. Z: A7 S3 _' ~: a9 b A字串8$ B3 P7 J6 R; W* D" e
3 Z) L0 |5 O+ V2 s. P& N4 U8 i
1、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。 v# O9 N, x- A2 S, }6 e% j `
2、为三多理论提供了下注的多面性奠定基础。; ?/ B( D% j$ Q# h U. X3 y& L
3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是 上上路.5 e" K* o4 G' [$ }% v% B2 B
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你的理论打法不错的呀,赢钱了应该是打法对你有用哦~来收藏下了解下了 |
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我现在还是研究一下理论打法,感激楼主的分享,我也来学习 |
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楼主估计也是一个理论很内行的玩家,谢谢老哥的分享。 |
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