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通过我几个月来对珠路理论的研究,
" o( U4 ?+ x, q- B
/ W/ ]! S- ~6 P: j发现了一个有趣的现象,, B( y2 I4 ^( I [
每一条大路, [& I/ ]( O, H0 r/ g8 H, W6 U
按2珠路排列,有2种不同的路数5 v6 R6 y( \; m2 G# F9 H
按3主路排列,有3种不同的路数
! k0 a1 n8 Q6 _7 T5 R) k. D) d% G按4珠路排列,有4种不同的路数
' t; ]4 s/ _9 ]0 s/ s% N按N珠路排列,有N种不同的路数。
7 |7 W8 ~/ q5 I; p5 J8 O, z什么意思呢,可能大家一时不清楚,
! R" U$ F+ `( ~. p' r, [我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。
( \1 V. Z8 v6 ^7 w5 _假设大路开这样的路:
6 ^ y7 @4 u+ A! h2 |12121212121212121212121212121212
/ i! I6 x+ k9 x够极端了吧- m @* ~( u/ j3 }$ P9 {0 O) y
按2珠路,就是BPBPBPBPBP.....$ z$ M B2 t' L/ A+ Q; ^) Z
如果我们去掉第一口,就会出现完全相反的结果:
) S; ^& h/ W; Y! X1 s5 ?# u, K21212121212121212121212121212121
+ X+ W, L' O0 U% s+ V5 O# I/ i变成了PBPBPBPBPB.......
0 v4 i+ j+ {% u& N8 s5 n如果我们再去掉一口,又返回第一种情况了。
H+ s/ I, G! a. u) H8 F+ `所以每一条大路,
. N$ C; r+ W# {- L按2珠路排列,有2种不同的路数。
- a, j9 \2 ?4 I8 A( ` l# I再举一个列子:7 J1 H7 e# @4 D* e
大路:122122122122122122。。。, q; i" K" Q. J8 X
按三珠路排列:+ J8 d* {7 o7 }/ y& R/ `* ~
122,122,122,122,122,122。。。9 P. z5 I( l& P/ ^+ j; t: z
去掉第一口,变成:' Q+ i! e; T2 {) {0 u
221,221,221,221,221,5 ^/ _! [5 a* Q" t' _+ v
去掉前2口,变成:
C$ J1 r, f: d) R% l# l# p212,212,212,212,212,6 A9 w+ O" A9 o2 S
去掉3口,又返回122,122,122,了- b, x9 {: ~; g! ?, e1 y7 ~2 Y
所以每一条大路,
# h+ R7 s/ N, D- p, S6 M* n; y2 _5 }按3珠路排列,有3种不同的路数。
& m: H( b A- d! Q/ i a+ U6 R7 ^同理:按N珠路排列,有N种不同的路数。
+ @5 V5 i+ Y& B: z' t* r8 s我提出这个的意义在于:7 g- n0 s; Y+ l6 u
字串8
$ t2 |5 ]' T! G7 G* y0 P# } y9 M4 U; J. @! }( f6 H5 l2 j
1、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
5 P$ n3 H# P& c0 S2、为三多理论提供了下注的多面性奠定基础。% e5 |( D! m5 E d8 O6 ?
3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是 上上路.: q5 Z p7 w4 z
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你的理论打法不错的呀,赢钱了应该是打法对你有用哦~来收藏下了解下了 |
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我现在还是研究一下理论打法,感激楼主的分享,我也来学习 |
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楼主估计也是一个理论很内行的玩家,谢谢老哥的分享。 |
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