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通过我几个月来对珠路理论的研究，5 R+ y* d$ ? k6 I7 G/ O) u4 H3 e/ f$ B6 Y) E3 O
0 ~+ T1 m; j" c
发现了一个有趣的现象，$ Q- J1 l/ X$ \, w/ X0 ~" O
每一条大路，- j# W# p' {4 j# C
按2珠路排列，有2种不同的路数1 _% l2 j Y8 @" u) {# f; m1 x) w4 Y- i3 C1 a
按3主路排列，有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z4 a$ t& Q7 F) f% K
按4珠路排列，有4种不同的路数! z- n3 x8 C# }2 a5 ]) Q$ u
按N珠路排列，有N种不同的路数。: n1 f3 R9 @ p% ]* C# A q6 a$ M) a4 N1 q
什么意思呢，可能大家一时不清楚，7 i1 a7 I( \( B, m, }) M( F
我举一个例子，假设 B= 1 ， P=2，T暂且忽略吧。7 f# f3 c1 ~2 l
& j! v$ E0 M, I假设大路开这样的路：! z ~0 G3 v. K' o5 A4 ]" }5 w# u3 N# d5 C' ^. f1 {) I. o
12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h
0 w. X7 U" u* u2 H/ C够极端了吧1 L( M; R. k3 o
按2珠路，就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F! E" \* k" [2 w3 r% G: Q6 E
如果我们去掉第一口，就会出现完全相反的结果：+ k: d, q0 \1 _0 O" ]5 o* w
21212121212121212121212121212121% t5 v# o. T6 ?; H7 U/ l% z
变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C" n7 D. d& ^5 E5 ^0 ?. W
如果我们再去掉一口，又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O+ R, W1 W, |/ ~* R
所以每一条大路，! R6 V# q$ h. c; z% O
. k( m& T& D P/ Z" E6 B按2珠路排列，有2种不同的路数。
9 q& I6 o' O& d. _/ a' J& Y. j再举一个列子：0 h. d5 R3 o' J
大路：122122122122122122。。。
& q$ F2 t, m% j按三珠路排列：1 t4 w7 K6 q3 n3 F
122，122，122，122，122，122。。。
7 P* p8 v) G+ O& Y1 E6 A去掉第一口，变成：6 G2 V! \" L' c" k: d, L5 ?+ D6 k+ l) ^1 i% D
221，221，221，221，221，+ R$ P2 d/ f7 Z, P5 M
0 } K6 q2 V$ o. X' V( j" l" L去掉前2口，变成：3 v1 q) z( ?2 f! }) U/ W
$ `8 k/ V3 G/ q# |) }7 w212，212，212，212，212，: y& l, B; I6 e- m. J# c) `
! ^8 \: q6 l& Y* }去掉3口，又返回122，122，122，了
; [; d& x5 U4 v0 {* ^$ E* J! F- C& }所以每一条大路，1 B. `/ Y5 }# X, v* ^' v( S
按3珠路排列，有3种不同的路数。
4 s( @4 a- O. I$ B同理：按N珠路排列，有N种不同的路数。3 h; g! `% \' o/ T: v4 e
我提出这个的意义在于：" v) X/ h3 }* D1 {5 J! a1 s. O
' L6 G! ^. r3 U6 i+ O字串83 L: R) G1 V- s2 Y+ Y
# g& x) O) x5 i) i2 D% U2 N- p, d3 [6 U. s5 J' [0 {1 A" m' k( @
1 ?4 J6 a* Y- d& [1、每靴的第一口为起点来编排二三珠路，与第2口，第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |
+ V# c1 U: f3 \+ l2、为三多理论提供了下注的多面性奠定基础。
+ A+ |' g% O9 V" A& U. g+ l3、某一靴牌，按第一口开始的珠路可能是 烂路，按第2口，第3口开始的珠路可能是 上上路.
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