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通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。
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假设大路开这样的路:
# t$ V7 l" o& J: B( Q% K& \) u
6 D- G/ \4 H: j$ i5 h6 G9 { 12121212121212121212121212121212。 c- E; \! M0 b1 a
+ b" i3 L. _. I- v) j' n
按2珠路,就是BPBPBPBPBP。6 @' U0 p8 C( T1 i5 z& |+ ]0 `/ N
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如果我们去掉第一口,就会出现完全相反的结果:0 {+ i& K! j3 T4 u, [
: D5 F/ P" c4 g8 q. t+ s 21212121212121212121212121212121。
o X6 K+ o" G+ ? z8 R* z
. I9 U8 B# S8 d t: D5 J 变成了PBPBPBPBPB。
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/ b: S/ u' b/ I' Q1 e) F 如果我们再去掉一口,又返回第一种情况了。 l4 k4 q4 B- b$ W( W
1 R! O" |$ `0 T 所以每一条大路,按2珠路排列,有2种不同的路数。0 p0 Y3 d9 P* _( ^" d- \
, C6 ?. \7 Z1 Z
再举一个列子:: [/ p: C. }! y' b3 u2 x4 }; p
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大路:122122122122122122。8 W4 ~: |2 @$ L1 {8 Q* x: n
3 k6 k$ Q N& d V# k 按三珠路排列:3 G6 G! `& v, G; S# ?3 d3 I# m
" [* u4 n: P( |4 O/ t
122,122,122,122,122,122。7 C) x* m! S1 d B
' H5 n0 ?6 N9 }; e+ ]/ D9 l4 L 去掉第一口,变成:
+ M1 p) l( E3 u/ |1 M) K# F7 s$ @" Y! [ Q' @1 F
221,221,221,221,221,去掉前2口,变成: S. A% q7 g' t t) ?/ A; H, G y
2 D/ p8 s1 X6 @+ H! z. [# @( K; t 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。
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& [+ H; u! g: O. _ l8 v 同理:按N珠路排列,有N种不同的路数。( y6 h) X, I! b: q
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我提出这个的意义在于:
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1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
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+ @; C4 Z8 g1 \7 U& K 2、为三多理论提供了下注的多面性奠定基础。: {8 s2 G/ f' b/ ?2 M) C: d5 |
! |* G6 \4 R. w1 Q% Y4 W 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。' n0 l; f C+ i/ @$ i
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