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通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。* z1 L, Q" @' \
8 ?' ~8 p9 J [! e6 u, ~; ~ 假设大路开这样的路:
5 }( Q: b7 w! v4 V
0 i6 {2 B2 H8 V- s0 [- c 12121212121212121212121212121212。, d4 }$ P4 \+ l2 a$ K8 c
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按2珠路,就是BPBPBPBPBP。
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+ H* d9 I3 `- ? 如果我们去掉第一口,就会出现完全相反的结果:3 q* c, g/ g9 Y' B4 o3 H
& _! [+ }0 I, }0 E8 }& ^
21212121212121212121212121212121。4 R; k; o2 \4 Y- K' `+ l
% J1 h1 a- v! e. N5 ] 变成了PBPBPBPBPB。
* f, A2 X+ d% M) s6 C% r. |5 V( B0 m: Y( F
如果我们再去掉一口,又返回第一种情况了。0 L0 S i0 x V( _0 g
, q2 z# e ~, a! f8 _, S
所以每一条大路,按2珠路排列,有2种不同的路数。
4 w& k" u! l1 U0 d* K0 k# X, `# c# k
再举一个列子:: P* u! W7 N3 Q' c, n, `# m
- N4 e0 |* @( W2 U2 y7 W1 j, N 大路:122122122122122122。
8 V% u; t" p* B
& ~" ^% y7 c# y+ I) |, T 按三珠路排列:
& C: m* y1 N: J$ `! l0 J, P Y1 @' S* f2 N8 |
122,122,122,122,122,122。0 G& N5 J. y# B/ r1 D; [
! L5 C8 x9 y0 q$ d( F" @" o 去掉第一口,变成:
' _! b% [! g; e" X8 s
" ~3 R% Z2 Q6 \ Z% u- x 221,221,221,221,221,去掉前2口,变成:; \8 J4 N) u! D9 q: V
7 n' V! g9 O% E/ o& e% f$ ?- K8 A 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。9 c' `9 S5 k$ L' d4 Y% t
* s& w) w7 R I8 A" E. z 同理:按N珠路排列,有N种不同的路数。9 I( H) f* u+ h9 Y+ G% t. G+ U
" @/ r8 z2 H5 X: I- W 我提出这个的意义在于:
# k/ o5 o$ [! w* V! {- P# i2 f: D- |) Q
1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。, b! p# X, T# `
6 U0 h x" i' \, E 2、为三多理论提供了下注的多面性奠定基础。
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# v: J( U7 S) @1 t 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。1 T" J; \; l8 {7 C
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