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* D- l. Q& ~4 b f
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通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。
& ~' C7 C0 M2 ^5 ^/ ^ }6 S: c$ Y/ |/ H# m5 [2 O
假设大路开这样的路:; o# V1 q; b4 K/ p# M4 [
, l. r5 b2 A6 f0 B' N/ ~
12121212121212121212121212121212。( P6 b4 C( n! i. p9 D
' Y" i8 o# A3 V* B4 e) U 按2珠路,就是BPBPBPBPBP。( H7 x% h. o+ @8 X, s- J
8 q; ?5 x1 Y! D' [
如果我们去掉第一口,就会出现完全相反的结果:. J( P J) ^1 T" t
$ c3 s* p( e. p7 ~0 P6 \ 21212121212121212121212121212121。
/ z) P6 n9 v4 }5 n# L, h- D$ _: Y/ P
变成了PBPBPBPBPB。
* C# p1 P$ y2 P( b* h0 R8 j/ Z% e9 E% |5 Y& W U
如果我们再去掉一口,又返回第一种情况了。
) S/ V, @ i; v: Y2 u" u3 C( z! r& d) O6 v3 w' p( M/ z
所以每一条大路,按2珠路排列,有2种不同的路数。
. S1 @* O' s0 r; R+ j# y" z
! F) L/ Y- O+ K p 再举一个列子:6 G1 [& K- A- a% o
/ b1 m6 N# [9 i! c, j; T; ] 大路:122122122122122122。* V! ~, i- H- I$ q# Z
; S/ U' Z) A( ~1 x0 D. F) | 按三珠路排列:
8 J. c0 a- ?" \3 g1 n* T3 s4 u* p/ E# i9 p; ~! N( E
122,122,122,122,122,122。6 Y6 a) `( D, Z0 o# ]6 M8 I% N
+ V% H' P2 F) ~- T 去掉第一口,变成:; F4 c5 f, H1 d7 ]& ?4 Y- q
1 Z" N2 i# h4 p. b. `
221,221,221,221,221,去掉前2口,变成:
/ i& b& c @; K' K7 A }+ Y8 L
: D2 Q6 M& j9 [* i& F/ N C, f 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。) Z# L% A4 C" t( f7 L( K% q
3 ~* m: v( W2 S) ]4 y7 z5 P 同理:按N珠路排列,有N种不同的路数。% s% o+ t" i/ c+ N9 l2 F
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我提出这个的意义在于:' [+ b' L7 u; R; w; v: ]0 y
3 r0 C8 A; p7 D9 k& i 1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
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2、为三多理论提供了下注的多面性奠定基础。* O) ]- Y) n p
; v1 x' j8 k# M6 k7 F 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。* _; K4 |( O" t3 \% E
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