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% Q# z9 c& }4 q' B5 P/ T, J3 E; T, z# ^9 _+ B2 _1 w4 f4 [
通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。
% H4 x* r$ c/ V+ O2 W2 `+ `
/ i/ Z' o3 }, r# E) G& q 假设大路开这样的路:: F# F9 @$ b1 I' y1 j' ]6 { Z
N/ d, q6 H* a F: w
12121212121212121212121212121212。
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按2珠路,就是BPBPBPBPBP。
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+ F" r! L. ^2 U5 k! F 如果我们去掉第一口,就会出现完全相反的结果:" i* I3 Q8 C' l1 M1 ~8 @/ J8 O
$ N: F8 A0 k( ]2 m
21212121212121212121212121212121。8 X7 e( Q L2 r3 U4 i/ L2 O
$ k8 T+ {; [# ]8 E
变成了PBPBPBPBPB。/ v" \8 I2 l/ S1 {, m( j3 j
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如果我们再去掉一口,又返回第一种情况了。. }+ o! \: Z, |4 o- m, j) @% d% y5 Y
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所以每一条大路,按2珠路排列,有2种不同的路数。8 I% x2 a- V1 g, e% j# l y) {5 E
" D3 X4 s* q2 O# ?
再举一个列子:
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大路:122122122122122122。! C7 ?4 n8 q& b% m" z
' @! Y: F" Y" r1 F$ b2 x
按三珠路排列:
# C2 s5 ?' N: v, k3 H: g4 |
a2 o0 h: x2 E& d# T; P/ B 122,122,122,122,122,122。. W3 f `( P! ~/ V2 s6 O
6 f" C- i1 J- T l 去掉第一口,变成:
" Y, V8 m& h: x. o, B4 s- }, [" U' ?! A- l! Y# ]" I
221,221,221,221,221,去掉前2口,变成:
E {" h2 d, ?5 X: m g+ k/ G6 H/ n/ q* E( z0 o9 A
212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。
a. }$ W! g) S, x0 l& ~4 C& Z: s/ F, l0 v! u* s& K# f0 B
同理:按N珠路排列,有N种不同的路数。
% p" d3 Z3 E8 ], h2 n N' o6 g+ }$ G O: T% ^
我提出这个的意义在于:, p) f1 ]% |) J. z
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1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。. W7 ]" [9 O! Z$ u
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2、为三多理论提供了下注的多面性奠定基础。
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3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。
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