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3 c' ?5 U% Y9 E8 o" O
+ k$ \3 a; N: K! D通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。
2 I, R5 `5 T: }* O. l
8 O: M1 _! r! ^7 G" B2 y 假设大路开这样的路:
0 j% l2 h1 T8 }! O1 t
9 X6 _3 a% [6 n5 m1 C 12121212121212121212121212121212。
" F. N8 G* A0 k
1 R6 s: {( R! V, `; ]4 I7 a 按2珠路,就是BPBPBPBPBP。
9 d* p( S) n0 `3 p8 p
# n6 F: l6 p. d E# k s* c 如果我们去掉第一口,就会出现完全相反的结果:; l% h1 W, c; f ~
( W; e: _* x, }- m r 21212121212121212121212121212121。
0 s6 B+ H. R2 {
6 S) x: d+ M% J 变成了PBPBPBPBPB。
* @" k9 X1 ~# o! q6 O2 M8 z4 @7 P4 t3 q" L0 w& z
如果我们再去掉一口,又返回第一种情况了。" f9 q2 m: U6 S; g( c' R
: E K+ D+ c( g+ J* c0 n
所以每一条大路,按2珠路排列,有2种不同的路数。
- V6 ` s- G* P
9 R( u1 E" i5 `0 u5 p V 再举一个列子:
# z7 X: a0 P$ S, F8 g, w5 n8 r# Y+ [2 {1 r
大路:122122122122122122。
- i% w8 Q8 v, D! t4 `- {+ U M3 J; x" p2 d0 |0 @
按三珠路排列:7 U1 S" O+ e: K9 H$ S
5 G( y+ z- l$ m7 F L
122,122,122,122,122,122。
m8 ~, o( d+ S$ y
& Z" E; T a9 E2 q 去掉第一口,变成:
3 ?6 @# P6 s3 `: `0 e0 i+ J5 ]+ Z* M
221,221,221,221,221,去掉前2口,变成:/ u- W! J8 U; ^3 W& ^! v5 @
$ s3 T/ B4 T9 {' R, a0 Z) }0 t
212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。& g6 U; X& S5 p# p5 r
4 U+ J6 [2 Z) X+ a4 K* B t+ t2 _
同理:按N珠路排列,有N种不同的路数。
8 d+ e) s# ?7 v# b7 b; I, F' n3 _1 s" L1 d( l3 V
我提出这个的意义在于:; K/ ]; |8 }/ u, d. p
& ?+ p. y+ d9 |( u, n; [" s
1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。) b! h& F$ V5 {4 p5 r, {# b
7 k V3 U2 [& U$ H' m* ?
2、为三多理论提供了下注的多面性奠定基础。- f- _* [$ ]1 s% q
4 U( L/ R# p5 f 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。' G# y. T3 g+ ?9 j. a% E/ R3 J
! P H3 X% j! d# g" J2 I
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