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! p4 ^# E! E3 W
3 T& H0 w$ M a; v/ X/ w5 `通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。) V0 E# C! x) l6 ~
+ w& z3 c) X* @. k, \# g
假设大路开这样的路:8 |' ~* F5 @' d$ c) m" j
; I/ B- k# z2 O# \7 d+ e: O: c
12121212121212121212121212121212。
; Z* a* M; {$ p& q8 P0 z8 t
( z/ H% ^0 W/ N& [2 i4 } 按2珠路,就是BPBPBPBPBP。. y, Z( s8 i( X4 ]$ w5 R
; P, n! V2 u; V. O0 J- ] 如果我们去掉第一口,就会出现完全相反的结果:6 _* I7 r0 a) Y+ T' T5 n: X0 Q
7 Y) P J( F% F5 C1 u3 r: G
21212121212121212121212121212121。
) d- n( `1 G8 F
8 i9 ^1 T! T7 g 变成了PBPBPBPBPB。1 ~* P" F! t: c2 [1 {: H7 C/ G l
# Q: P3 w, d& q* N7 l4 @1 K 如果我们再去掉一口,又返回第一种情况了。, W' Z, t H. Y8 c, r
( P3 M8 p: q, z+ m- y% p' q 所以每一条大路,按2珠路排列,有2种不同的路数。
5 q: I# N' Y4 V! R' Q
# o9 Z6 n( l0 O, L 再举一个列子:
' x$ t& L8 o% A& H0 j+ i
' I$ U) W5 `/ j5 n 大路:122122122122122122。! C, {& g: H, r1 A- X" F
; d# R3 t8 U: b2 q 按三珠路排列:
) |3 V9 C2 R0 ?2 `+ V4 [% B" { g, {/ z
122,122,122,122,122,122。 z) i+ \5 k% G
4 E$ U, Q+ Y* S% l5 ~4 {$ q- [7 R 去掉第一口,变成:
( A' O3 ^% T$ ]# W& y5 }
. Z$ k) C: F4 `+ V2 d9 z! F. B 221,221,221,221,221,去掉前2口,变成: ?- T7 e7 c8 m( q) Q; P- W! T
8 V! u* B" s+ ?! n6 R 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。
! l! \/ f1 `- m5 U5 s& X) Z& F5 S9 |- C. m% m9 }9 `" _
同理:按N珠路排列,有N种不同的路数。+ N) k' V" W% t. b( V4 M8 S1 O
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我提出这个的意义在于:$ V1 n; V; P# L
( ?/ Z3 m% `% ?3 N' M
1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。6 h2 S2 g U9 @& G7 j$ A3 |
5 _- N; G2 P- z8 ]+ d( t
2、为三多理论提供了下注的多面性奠定基础。8 W3 L! v( z; e/ J& B
5 M- w: i4 M% P- W- ?# c+ p0 p
3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。3 S0 [9 Y9 n5 u0 _8 Z& G
7 w0 P# T8 v0 T- K ^9 F A
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