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8 j% ?. w* ?$ l. H2 ?" v0 ]
7 l: M3 Q" `7 Z通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。
( t; g8 _4 N8 w# [1 X5 J- t) v8 A5 `& h! h! X* [
假设大路开这样的路:4 K) y- N8 ]) {: ~% u& G4 p b1 x
3 i' l: F& Y# L2 x2 `4 | h- \ 12121212121212121212121212121212。+ J! f; o( u. E* t+ W- t
8 E8 R0 t5 Q" J+ B3 u3 ] 按2珠路,就是BPBPBPBPBP。7 u, a/ T5 V6 e; N9 g$ b
# ~( t3 ]6 X1 @1 | 如果我们去掉第一口,就会出现完全相反的结果:
: B) |" Q# [) a* e
& h7 w- a$ Q6 u" f- m k# \6 {( e 21212121212121212121212121212121。0 F+ j) q5 Q, p/ A" O4 F
# \! [) l$ V3 h( L$ ? h% G8 j, y
变成了PBPBPBPBPB。& ~) c# t; D1 ~+ q
. H6 `5 m7 v9 L0 O6 _: e 如果我们再去掉一口,又返回第一种情况了。* l ~) |( Z" w/ P
( L2 o7 `2 f" k3 `! y" J
所以每一条大路,按2珠路排列,有2种不同的路数。" g+ s4 O1 q0 p# V* f
. q0 Y l2 h s" |2 w/ v1 N 再举一个列子:
4 n* l" ~: o6 d9 N$ L4 z/ m
) y2 f, R: C$ c, D, d. ] 大路:122122122122122122。6 u$ x7 l: r" z
( e! z! a" a$ y( a
按三珠路排列:
, X0 A/ \+ W- K% [* E2 {# w( H8 r% L
122,122,122,122,122,122。
1 r i6 R! M0 ?
$ v- L9 e) K @( ?) f0 R 去掉第一口,变成:/ \. K/ K4 i, j. z' k) b7 u! S' w
4 \3 J. W4 ^# I" z" g: Y& Q
221,221,221,221,221,去掉前2口,变成:
2 P% G# L! o8 S1 ~8 H; r4 H- d3 J8 p
212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。/ i2 e# S7 O8 W3 y& k0 V% Z
D; @5 ^* q/ b& g6 b m 同理:按N珠路排列,有N种不同的路数。$ z, }4 j/ c$ F; [7 f& j, U
9 p. X! Q! h5 C2 ?; s9 k
我提出这个的意义在于:
2 u6 ^% g0 I: e7 p
, a% ]: o2 d% |! B. h4 B 1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
5 B& n/ p+ k% M! L+ H- v9 p! g Z+ `" b: w, r: b/ W0 }/ D8 G4 [7 D
2、为三多理论提供了下注的多面性奠定基础。
/ G' a- T- Z3 P0 U U6 m$ r- K. I) O0 A9 H L8 R! r' @# Y
3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。
$ Q$ f( o+ q! x! x7 t9 q7 s+ g2 p2 ]4 T% A+ M$ N
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