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[lastpost] => 2646158 【星宝】4月30日投注流水87106元(单日流水) 1714807539 如梦的生活
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在博彩中怎样才能赢钱?买缆就可赢钱吗?如果你不断的缆,缆一旦断了就要赔大本,反缆一会必胜吗?要促成买缆必胜,要有一些讲究的。今天分享玩百家乐中如何反缆必胜。
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/ o/ y; o+ W& N0 @# o要促成买缆必胜。首先我们要了解游戏规则。一般博彩都会设一个注码上下限的比例,最普通的就是1:150。例如最低是100元,最高,就是15000元,视个别博彩来定。在亚洲的博彩,很多是以全赌注总和计算;在美国等地方则以每一位赌客独立注码计算。目的都是一样,因为博彩要保障本身利益,如果不设上限,无止境地复式加倍又加倍投注,始终会给闲家买中,博彩就会不利。那麽什麽上下限都会介乎最少的1:100到最高的1:200呢?原因是开赌的人也计算过或然率,令闲家即使肯博,长期买缆,也要冒输大钱的险。
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下表就可以看出买缆的情况:+ c8 `( n; y7 _4 _
8 J& o$ J1 J; ~ n( }$ \- o可以看得出最尽只能买到第八铺,第九铺已超额。如是者,必须於八铺之内买中,否则就要断缆,一次断缆,所输的钱,要连续赌四盒牌不断缆才可赢回损失。经统计及电脑分析,要达至长期不会断的缆,至少要十铺为标准才可保障长胜,但十铺又刚好超过了注码,所以是有矛盾,不可行。任何一条公式缆,无论庄闲的次序是如何排列,9铺之内还是有机会断,十铺以外则机会较微,愈长则愈难断,这纯然是混合或然率道理所在。换言之,没有永不断的缆,即是代表有必断的缆。非常正确,想缆不断可能很困难,但想其经常断就不成问题。特别是四铺或五铺的缆,差不多每一盒牌都会断的。因此我们就可运用这个逻辑,或然的东西难赌,必然的东西自然是易赌。0 E$ y7 e! I3 Q" l, I8 a, h0 b
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正常的买缆会是:输了第一口买庄$1000,第二口买$2000,输了第三口买$4000,输了第四口买$8000,直输四铺后,第五口买$16000。这麽一旦连开五铺闲,就马上断缆,一输就是$31000元,亦即要赢回31铺才可打和。这个方法基本上可以断定,长赌必输。因为出现连续五铺闲的情形多的是,一盒牌内断三次都不出奇。要赢就要做刚刚相反的动作。每铺都是买闲,如果开庄,输了又继续买闲,反正每次输都只会是输掉一个起步注码。如果开闲的话就不同了,第一铺开闲买中$1000元,第二铺就买$2000元,再中第三铺就买$4000元,中第四铺就买$8000元,到第五铺就买$16000元,全部连中五铺闲的话就赢$31000元,一盒牌内能中一条缆就不会输钱,中超过一条肯定赢大钱。
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经统计,平均断得最多的当然是四式缆(四铺连续),大概每盒牌有二到三次。五式缆则平均每盒一到二次,六式缆则每两盒就有一次。七式及以上就不会是每盒会出现。所以五式缆会是比较可行,既是常见,也可保持不俗的利润。赌这种反缆的方式,是需要相当耐性,必须要坚持信念,相信这种现象一定会出现。输了前段的不可气馁,一次遇五闲就可连本带利赢回来。另外,有的时候在一盒牌的前段己经出现连续五次遇了闲的现象,那利润己到手,已经可以再等第二盒。问题是如果长期只赌一方,庄或闲,那会令其他人觉得很奇怪。
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所以总结一条公式如下:依以上的次序,按序投注,赢了第一铺庄就买闲;赢了第二铺闲就买第三铺闲;之后再买庄,到第五铺又买闲,全部中齐就重新由头开始过。不要担心,这个排列次序,差不多每盒牌都有现。7 i% p' y+ L9 S7 k5 S Q
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我们对百家乐投注法中如何反缆必胜有了一定的了解,要掌握这种方法不是简单的事,还靠我们的领悟。
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