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通过我几个月来对珠路理论的研究,5 R+ y* d$ ? k6 I7 G/ O
8 O2 o$ M( Q- F8 ~+ \# m- k9 D4 O: A: D; v/ S, F7 n& h! C
发现了一个有趣的现象,2 _5 M. @( a6 A( `( X
每一条大路,
0 d2 F9 k! g6 I: f7 D/ T按2珠路排列,有2种不同的路数1 _% l2 j Y8 @" u) {# f; S; e; J/ z' d" E$ B0 ^
按3主路排列,有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z
& N: _) p% G3 L/ m按4珠路排列,有4种不同的路数
) l% k0 b3 q9 P Z' M4 g$ B按N珠路排列,有N种不同的路数。: n1 f3 R9 @ p% ]* C
; Y, m8 j K" q5 u什么意思呢,可能大家一时不清楚," }9 s$ \) S; @
我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。7 f# f3 c1 ~2 l
. l9 a$ o2 n& ~- S, @! x假设大路开这样的路:! z ~0 G3 v. K' o5 A4 ]" }5 w# u
9 [5 ?' k. j* z# i# V7 \12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h" N) X" C7 W% N8 Y, u' g) L5 r
够极端了吧
+ ~( m# s7 S1 o j* A按2珠路,就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F
7 t G" ~' x8 e$ X2 f6 a! _如果我们去掉第一口,就会出现完全相反的结果:
G, a6 q# W) ?% [6 y P, A212121212121212121212121212121216 G/ }- H3 U8 {8 |" {
变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C- r7 ~+ w7 O+ h$ d+ F9 N
如果我们再去掉一口,又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O
9 C3 V. @8 c% r* o% f所以每一条大路,! R6 V# q$ h. c; z% O
8 D; k( x. P, M, s) J; e# h1 _按2珠路排列,有2种不同的路数。
+ B& }; K- p, W; |再举一个列子:
7 z6 T" p; f7 x5 N8 f/ `( {; k大路:122122122122122122。。。* G3 L; W3 ?; Z9 Z
按三珠路排列:/ o6 [7 _$ E. b& S( X9 S
122,122,122,122,122,122。。。, q4 X; f* W3 R- ~* k. {9 u; D* L
去掉第一口,变成:6 G2 V! \" L' c" k: d ]! h9 _- S# Z8 h8 Z
221,221,221,221,221,+ R$ P2 d/ f7 Z, P5 M
. Y4 W5 ]& I0 e. W去掉前2口,变成:3 v1 q) z( ?2 f! }) U/ W
' w& U) W7 I+ b& t# L212,212,212,212,212,: y& l, B; I6 e- m. J# c) `
! q4 F$ m! R+ @- l9 z去掉3口,又返回122,122,122,了
! z( B0 }) M, B所以每一条大路,
% {' @1 s5 \( h4 I, r按3珠路排列,有3种不同的路数。
7 Y" t; T) d6 y3 T3 C; {同理:按N珠路排列,有N种不同的路数。5 d, m/ n8 C! y% e8 i, Q1 k
我提出这个的意义在于:" v) X/ h3 }* D1 {5 J! a1 s. O
8 t% E- K* O0 z% P字串83 L: R) G1 V- s2 Y+ Y
& \& n3 u @1 k1 \: _& b& r) Q! Q4 Z- p, d3 [6 U. s5 J' [0 {1 A" m' k( @
, @8 o# }" ?9 _& K1、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |
7 H( C; F3 ^" [) |# K2、为三多理论提供了下注的多面性奠定基础。
$ q7 G) M/ m$ \' f/ S) g: C0 @3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是 上上路.& ^; M3 V% N' H" a, E
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