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通过我几个月来对珠路理论的研究,5 R+ y* d$ ? k6 I7 G/ O x) G: B; }+ K+ x) Y6 l
) y3 v2 u, Y8 I* k3 ~7 `# i9 w发现了一个有趣的现象,
* K! U9 g5 v3 M+ P; m, U每一条大路,
* C& N5 G+ J3 h: l按2珠路排列,有2种不同的路数1 _% l2 j Y8 @" u) {# f$ J" q' a- y% y C n
按3主路排列,有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z
0 A7 {) t: y5 q按4珠路排列,有4种不同的路数
! p0 g2 k" t1 G- G, \按N珠路排列,有N种不同的路数。: n1 f3 R9 @ p% ]* C1 b) Q* }' j" R
什么意思呢,可能大家一时不清楚,* v5 H' ^) R8 I3 [
我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。7 f# f3 c1 ~2 l
" u) T V/ U8 e* [! ]假设大路开这样的路:! z ~0 G3 v. K' o5 A4 ]" }5 w# u" U% g6 @* S( z9 G4 P0 F4 y
12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h
* h3 o8 \ c5 G5 q6 G够极端了吧$ w- O% Z# b+ V: j- t' V
按2珠路,就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F
# W/ P$ N R* P4 _3 E: Z如果我们去掉第一口,就会出现完全相反的结果:
* X; `. F) P1 o4 W21212121212121212121212121212121' b; @/ c d1 S+ t4 D; ~6 E+ T
变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C
$ b, C$ [# r9 j+ e: i' k V/ }如果我们再去掉一口,又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O
& a7 O" J; G# L/ G8 r, n所以每一条大路,! R6 V# q$ h. c; z% O& |" W8 {2 d8 I: ~! Y, r+ `) U# z
按2珠路排列,有2种不同的路数。% s; Q* y, o+ I2 a
再举一个列子:& D. x9 I" n l" q# P5 W1 ]* x" {( e
大路:122122122122122122。。。
0 l& x, P; J$ f2 ?按三珠路排列:
4 O- F. Z$ c( p% |/ m122,122,122,122,122,122。。。6 e' u! T4 n- q. w5 G% } |
去掉第一口,变成:6 G2 V! \" L' c" k: d
; t( f; \4 `2 x9 ] k1 W2 |" s221,221,221,221,221,+ R$ P2 d/ f7 Z, P5 M0 P; Z* v2 [8 P% L. a! Q8 _5 a
去掉前2口,变成:3 v1 q) z( ?2 f! }) U/ W6 z! |: g( f3 m) a: n3 a
212,212,212,212,212,: y& l, B; I6 e- m. J# c) `" O# c1 C$ {: z4 ]$ t2 R) X3 R
去掉3口,又返回122,122,122,了9 A$ d4 z$ ~7 v. R$ ]
所以每一条大路,
# ` m" h7 G) S) K( E5 Z% N' Q按3珠路排列,有3种不同的路数。
2 ^" J( y" C: O5 N( c同理:按N珠路排列,有N种不同的路数。
% Z, c7 G, \5 _2 p- Q% e我提出这个的意义在于:" v) X/ h3 }* D1 {5 J! a1 s. O: Q0 K0 R" B- G2 K5 x
字串83 L: R) G1 V- s2 Y+ Y3 m; g M( p8 V- h! Z
- p, d3 [6 U. s5 J' [0 {1 A" m' k( @4 \) n# Z2 D& a+ p# P
1、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |
9 Q; ^/ e" X' Q2、为三多理论提供了下注的多面性奠定基础。. v* {0 H: Y" o0 s6 r) J B. V
3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是 上上路.
7 u: I' F C" H% l |
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