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* B# T2 _& A, {* [+ a* G. `
! p4 k _4 e. H# }通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。
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假设大路开这样的路:. M1 E. ^0 U( W6 Z n
7 Y$ |2 W: g& m7 ~$ U, I6 z
12121212121212121212121212121212。+ D( |0 R. J- F5 ]2 Y7 _
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按2珠路,就是BPBPBPBPBP。6 a4 ^8 { r5 M+ Y4 B, ~1 w
; }3 G% B$ R4 I" g& z/ C, D 如果我们去掉第一口,就会出现完全相反的结果:
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. J3 u$ ^! V. k) G: d( U 21212121212121212121212121212121。
v' r L! R+ |' ~! Z8 R0 q, \; j1 @7 E- ?5 q' V& s0 j: k
变成了PBPBPBPBPB。5 z: y% ^$ |3 F6 P( N8 N+ @' x _
8 h0 r, Z; w& t2 q" _0 j 如果我们再去掉一口,又返回第一种情况了。
6 X0 X2 _% }* z
9 B5 H; ^7 H% }8 ? `0 s$ E8 d7 ^ 所以每一条大路,按2珠路排列,有2种不同的路数。3 b# }; _+ b0 M5 G$ q6 S
/ m/ }$ ]- B! u4 Y8 R4 e 再举一个列子:
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, X' Z# v8 A' ?" l: q& B$ X 大路:122122122122122122。
$ k2 z# L8 M' \, f' k& u7 m0 r6 b
. ?4 M; ]$ n1 m$ t6 b6 u( v6 k( Q J 按三珠路排列:
0 f7 Q4 P. n1 U: D
f5 v" J% k- r3 S ? ^ 122,122,122,122,122,122。, e# U- e" p: ?7 t/ K
7 S2 y9 D# L) D* \) S# w, q, q2 _
去掉第一口,变成:" M7 {7 x/ @9 \# Y( a, O
G! L: `( a1 }) f6 \ 221,221,221,221,221,去掉前2口,变成:
) D4 G& m" s2 K: H" ~3 P' ^# R3 l2 }8 L
212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。& p& N0 h! N, U% D" X- p
9 @, e4 v+ ?3 E2 N$ V: t+ o 同理:按N珠路排列,有N种不同的路数。1 Z4 l9 D/ u- l/ V. O( }1 V
# Q- |$ N# r2 a, d# k9 O 我提出这个的意义在于:
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1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。7 h8 r+ J$ n5 M9 ^7 K$ i. }
( S) E0 {# d( t8 `- }( R% V 2、为三多理论提供了下注的多面性奠定基础。
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3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。9 v$ @" ]' [" e5 t+ U! h- m
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