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眼里没有庄闲,只有连和跳,因为庄闲是一对一的,而连跳都是一对二的。理解也好不理解也好,这个讲起来费劲,就不过多讲解了,你只要记住百家le只有连跳没有庄闲就可以了,通常大家所看见的大路,第一行是满的,从第二行开始才有洞出现。6 y1 r0 f1 _; j+ W5 G
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用什么办法把第二行也变满,让洞出现到第三行去呢?这就需要重新排列大路。一种全新的方式去排列大路(又是新用什么排列,用连,和,跳连就可以比如大路是(随机的)" e' U6 v- ]% W" F. v4 {
. o7 t/ M2 E) K; H) w
第一行:OXOXOXOXOXOXOXOXOXOXOXOXOX(第一行永远是单跳)
5 v+ W+ ]# t7 g" _2 M: k. o, R9 {5 |
第二行:O X X O O OX O X (第二行开始出现洞)
" y( x. W( E0 k
) p" ^' c' K5 r 第三行:O X O X X- d( ^4 N/ o$ F- O5 ^
# e E! ~: W. Y; i) y" X( X$ o
第四行:O X X# {4 }4 y4 ^( r! F
/ C0 s5 Z8 u" E' |9 P 第五行: X
2 g- U7 w$ X% D7 N, ^1 r: ?! b3 s5 J0 l- N2 Q7 B
那么新写出来的大路是怎么样的呢?
! a) d; ^* a9 K' }) l3 ]9 @6 j
" L* n5 Y7 h, |4 T1 H 记住一个简单的口诀就可以写出新的大路:1.连是连;2.跳连也是连。5 u5 @! H5 c- W% S/ s3 S2 A% L; [/ Y3 F
1 u9 Q% K' \+ p# j& ]# g2 @" W 如下(大家凑合着看吧,实在不行就自己拿笔抄一遍,和上面的路一一对应。)0 X! g+ p8 l6 e) }* ]/ I5 ^9 S
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第一行:OXXOXOXO OXOOX(第一行不再是单跳了)' k! \8 [& C+ D+ N, ^$ b. `( T
9 g4 k7 u8 @, \- g
第二行:OOXXXOOX XXXXX (第二行也是全满的)% V5 X- ^2 @8 [% p
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第三行:OX OX XO XOOX (第三行才出现洞)' a9 }& b8 K: k4 _1 L
: E0 K. n+ G R8 }0 `& i 第四行:O XO O XXX ) W4 E; |2 R" G
1 l ?" P! m2 `5 g6 {& k2 w8 |0 T
第五行: O, y, q2 L Z `9 ^/ C6 L# I1 N$ l! n
% C I0 @8 d- Y& N 通过以上排列,大家看见了,变换了组合方式以后,大路不再显的那么杂乱无章了。每一列要么是连,要么就是跳连。这就似乎是最初期的关系形态变化组合排列,通过这样的排列,从形态上看,整个路只有12个形态上的跳,其他全是连贯的(可能已经有人开窍了)。5 s# E7 _8 c( D* p. H& _
! A5 e0 E! S) n) C$ i6 U
大家看第一行不再是完全的单跳,第二行没有洞的出现,第三行才开始出现洞,每一列最少是2个符号,通过这样的形态组合,实际上是减少了原本大路上的跳40%-60%,比如原来一靴牌60把,基本上是30个跳。30个左右连,而且是间隔无规律,杂乱无章的,按常规跳连的次数是基本一致的,周期越大,数字越接近。
9 Q( H/ p' B2 ]2 e+ J" `* K
# ]/ ]4 }1 ?- G; o4 G# b0 Q6 e 通过配列 可以把原本大路的跳精简到10-15个左右,相反增加了40-60%的连,以上是对大路形态转换的最初级形态,相信已经能对大家有帮助。至于怎么样去下单 ,一目了然了。
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