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& Y% j6 r! W: S; p+ S通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。
5 m$ A! H" `, p3 W* ~# X! F7 R$ \; L1 v9 b* X
假设大路开这样的路:
7 ]4 b$ ^4 N: \2 q" v+ x* I
4 W1 F' f9 Y; i( V 12121212121212121212121212121212。9 P9 Z' v8 w' z' k: e
# q6 k! Z; K1 z) g- e& E/ d
按2珠路,就是BPBPBPBPBP。
8 ^8 G, u4 ?3 @& w9 W. A- D, ~" V6 h- `/ h: @/ Y% I
如果我们去掉第一口,就会出现完全相反的结果:* n `8 D3 D( Z6 v
" d- n0 {/ L/ h
21212121212121212121212121212121。2 m0 k, V2 s0 p9 o+ s* x A! C4 ?
v. y! E# q* B
变成了PBPBPBPBPB。
& I3 z9 T% I. x6 s0 s: p* s# S/ N/ L e
如果我们再去掉一口,又返回第一种情况了。
9 h' N! I8 T* X% K) T$ g7 d3 o( i% k% m/ n: `( S1 e# u
所以每一条大路,按2珠路排列,有2种不同的路数。+ s+ g. P0 s7 D+ A2 z5 z# h# a0 b @
# M5 L- C3 K* a: ?0 i0 a- T$ m/ O
再举一个列子:9 S- o$ O, M# l7 ]0 i' ^; B
V( h# S' P+ C- h 大路:122122122122122122。+ x. }; j) v8 ^8 n/ s
6 w& o- M3 e, S# U$ C3 r 按三珠路排列:- r s$ ~. e8 e' ^: M
: W" X6 P) Y& S1 ?" M! c" j 122,122,122,122,122,122。
4 Q! g/ a+ M, G9 l3 L
- s `; y( H+ F5 V 去掉第一口,变成:2 x) c+ T! z! `% ^9 N
' ~ a/ ~* M7 j 221,221,221,221,221,去掉前2口,变成:7 ~* l: ?0 K" s9 R+ \" b
7 K' ~8 S, E0 o% N$ G
212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。
: H) f; |% {) x+ }( ?
, c1 e# y# f! i2 n0 X0 `+ o 同理:按N珠路排列,有N种不同的路数。9 g! g5 Q1 p: p
1 k, d+ B2 X4 g$ G- J" u, I/ w X 我提出这个的意义在于:% s6 v1 l" S4 Y7 ^' a4 E: Z* U
1 H* q Z" S! c u- \6 o
1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。% Z6 |/ t6 a9 r0 H! w
6 g4 h2 ]1 ~8 y B+ S 2、为三多理论提供了下注的多面性奠定基础。5 N2 @: G8 V4 ?4 {( Q
$ R5 k! ?2 E3 c u, F3 E1 m& o- y
3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。- ?' u& f; V; r/ ~1 D
" `3 Q3 ]% g M* f* G4 ?# a9 `) g/ _5 v9 i* S3 ]3 d3 `
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