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通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。: H& W# _! Q) v5 L
" n$ M( N0 B+ x8 h# m 假设大路开这样的路:
" x1 ^7 ^& H; L' A k! W8 j9 W8 G" F$ \. B5 x# {7 K
12121212121212121212121212121212。
+ u8 |0 O8 _; V6 Q. T' R9 R( j" H ?$ o% E# @1 N( [
按2珠路,就是BPBPBPBPBP。2 k6 {, m% W. \0 r0 N* O, G
' D% }; o/ i8 t! h% [
如果我们去掉第一口,就会出现完全相反的结果:% Y- E4 b/ H* G. J
. i% u/ N2 M2 T+ k1 A+ F- J8 M 21212121212121212121212121212121。! t8 L" C/ m4 P! l
3 x9 F0 T v5 G b. Q, ~" v9 z. Y6 K 变成了PBPBPBPBPB。& D8 }7 [/ o8 f. _2 I
# D5 _3 s N$ H
如果我们再去掉一口,又返回第一种情况了。
" n! ?! g: S+ w7 L
. y; r- c B$ Z8 h- u 所以每一条大路,按2珠路排列,有2种不同的路数。
3 k, B8 `8 b* ]" }& e7 `& V
6 @% \1 q' e5 A% @2 ~9 }+ M' M 再举一个列子:
" L6 [: T( C0 L" w' Y7 }: g0 P7 l$ c" b& I9 y5 g
大路:122122122122122122。* u+ T1 B+ y" I# L8 u/ f
# N D2 p Q/ D& P: P 按三珠路排列:5 ^, @# [5 w$ J0 t4 _
9 Y$ E1 i/ R2 K9 R) E" h* |4 t 122,122,122,122,122,122。' M3 R* B( s6 r
' u1 P8 t" \$ r r F0 q" }+ q8 i 去掉第一口,变成:
$ ~2 Z G+ i3 i/ R9 }6 {
, `" M* z) y. u: F# {- a$ P 221,221,221,221,221,去掉前2口,变成:: f) _$ l5 i" b. G
! b4 e4 _! |# B* R
212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。% G8 r! f; r) a6 f0 Z8 M# R
# c" b! T3 F& i* c4 q
同理:按N珠路排列,有N种不同的路数。
" O4 u. |8 t/ _$ j3 S3 {3 N- j' ~- W
我提出这个的意义在于:: X; j9 f% x+ W+ S5 \
Z2 |% @+ O7 I
1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。( H9 ~0 {: b) i" O$ n/ G3 n
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2、为三多理论提供了下注的多面性奠定基础。( @# b" F2 u! }+ G* O
2 ^! u y3 o, P; C3 b0 d7 x, w( P' ^ 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。# H0 V# S! s) |. v$ d, X( _. t
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