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[lastpost] => 2637857 百家乐打法-积小胜为大胜-转载 1714833466 ieerxwcbb
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很多玩家都在苦苦追寻百家乐的连赢玩法,但是对于连赢的认识并不深入。其实百家乐连赢概率和连赢策略是相通,只要摸清了游戏特点,才能找到制胜方法。
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一般来说,
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二连赢的概率是25%( _7 _6 r$ s( |6 ~
$ e) h& {2 P3 @; p! o8 v三连赢的概率是12.5%
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四连赢的概率是6.25%
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……+ u; D0 O: P! a) D+ Z, l$ r/ R+ A
, W. J; E0 \# K/ `3 J十连赢的概率是0.09765625%) c! P) P | N* r3 f7 b b& ]
2 ?/ V' m, m, a- V* k这些概率值是所谓的相对概率,也就是二连赢25%的意思是只连续抛硬币4次之后,会有四种结果,二连赢就是其中的1种,所以他的概率是25%,同样的十连赢的概率也是基于1024次的10次抛硬币的结果组成。
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百家乐的真实概率含义是:
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. I3 X5 \4 i. i) o( Y) g. e假定一个口袋里有很多个球,其中有1号,2号,3号,4号,5号,6号,7号,8号,9号,10号球" t/ _) @/ g1 |. I5 O' t
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1号球有512个,2号256个,3号128个,4号64个,5号32个,6号16个,7号8个,8号4个,9号2个,10号1个。
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- ^5 |) G. L ~: O O% ]你要做的就是在这么多球里面每次摸一个球,然后放回去,再重新摸。如果你第一次摸到10号球,第一次一样也可以再摸到10次。* Z% e4 @! D6 y) R1 `: j$ D% j& y
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你每一次摸到的任何一个球的概率都是存在的,除非你摸无限次,才能接近之前提到的概率。概率在个体和短期内是无效的。" ?, M. v/ z6 V1 x7 w3 ?$ y! |
3 \" E$ |% y1 x. }' Y" c另外一个说法是,1 n3 H7 k* n5 Z! r
: E# ^3 Y* E( O5 w1、百家乐不是每次摸一个球,然后放回去,再重新摸,而是每次摸一个球,不放回去,再剩下的球里重新摸。
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2、概率在个体和短期内是有效的,牌入盒后出闲的概率是:49.32%,但是随着发出的牌的变化,牌盒内所剩下的牌数量的减少,他的概率就会每时每刻都会变化。3 W6 V2 ]# L c4 Q1 r
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再把这个概率代入期望值公式,当+EV出现就下注,就会做到平均赢。* J5 X. z0 \9 f5 x- W
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平均赢只是长期而言会赢,短期也可能会被震幅消灭,这时就要算标准差,再接合你获得的优势,按凯利值下注就可以做到破产风险最低,利润最大化。9 x$ O! r C0 e, z% ?7 [
5 j( r3 Q5 g+ D' g1 N6 |, x" _0 j对于这样的说法,百家乐玩家的解释是,首先,百家乐肯定是每次摸一球个放进去,只是袋子里的球和你的数学模型一定要配合。2 S' `' R7 l/ o+ I
) _: w9 ~. I4 q" R举个例子,如果你是打庄闲的,袋子里永远只有两个球,每次摸完一个之后要放回去,然后再摸。这个概念是不容置疑的。- D3 ]1 m4 B# X0 c% ]
& \5 I, \( J: X+ @: {第二,因为大数法则和算牌对百家乐的无效性,牌盒内所剩下多少牌,对庄闲的比例不会发生任何的变化
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第三,凯利公式的问题在于:形而上学。9 ^/ _, g& b+ O9 d5 b
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首先主观假设了一个不成立的底部,玩久了一定会遇到被爆仓的概念,当然任何一种模型都会有爆仓的可能,只是单纯的凯利更容易爆仓而已。研究的方向是多维+赢进补偿,玩过Diablo3就知道在Mp8的难度下,打到钥匙的可能性是80%。
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事实上,你玩的时候,基本上每次都能打到。
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因此,百家乐连赢概率和连赢策略,对于不同的玩家有不同的理解,如何找到适合于自己的玩法和制胜之道,是每个玩家都需要积累实战经验去摸索的。
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