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很多玩家都在苦苦追寻百家乐的连赢玩法,但是对于连赢的认识并不深入。其实百家乐连赢概率和连赢策略是相通,只要摸清了游戏特点,才能找到制胜方法。1 ]! Q) P @7 C
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一般来说,
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二连赢的概率是25%' G+ x; o# Y& j- ~2 N+ D
# v& w1 E" R U" p% W& X+ B" V- @6 A3 c& T三连赢的概率是12.5%
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四连赢的概率是6.25%) q& W% A ]6 f& K' l2 I, {. f* j1 b& h
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……
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十连赢的概率是0.09765625%" y$ u/ _9 s4 ? x# s! s# Q) E7 E5 f
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这些概率值是所谓的相对概率,也就是二连赢25%的意思是只连续抛硬币4次之后,会有四种结果,二连赢就是其中的1种,所以他的概率是25%,同样的十连赢的概率也是基于1024次的10次抛硬币的结果组成。4 L1 I7 o% o+ R1 f; u2 p1 n" i/ R
) ^* q% s' ^& c9 I" n1 h$ m百家乐的真实概率含义是:
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假定一个口袋里有很多个球,其中有1号,2号,3号,4号,5号,6号,7号,8号,9号,10号球
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1号球有512个,2号256个,3号128个,4号64个,5号32个,6号16个,7号8个,8号4个,9号2个,10号1个。
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你要做的就是在这么多球里面每次摸一个球,然后放回去,再重新摸。如果你第一次摸到10号球,第一次一样也可以再摸到10次。
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* f j2 A0 V! a9 [: P, B你每一次摸到的任何一个球的概率都是存在的,除非你摸无限次,才能接近之前提到的概率。概率在个体和短期内是无效的。
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, H5 j5 c* w) P4 ~8 i5 y; ~+ S; l另外一个说法是," T6 ~; o% v; L3 ~ I/ k6 u
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1、百家乐不是每次摸一个球,然后放回去,再重新摸,而是每次摸一个球,不放回去,再剩下的球里重新摸。
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4 l. u$ \6 H4 t2、概率在个体和短期内是有效的,牌入盒后出闲的概率是:49.32%,但是随着发出的牌的变化,牌盒内所剩下的牌数量的减少,他的概率就会每时每刻都会变化。+ z0 R9 o4 C+ ^; `/ l8 k
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再把这个概率代入期望值公式,当+EV出现就下注,就会做到平均赢。
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平均赢只是长期而言会赢,短期也可能会被震幅消灭,这时就要算标准差,再接合你获得的优势,按凯利值下注就可以做到破产风险最低,利润最大化。
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对于这样的说法,百家乐玩家的解释是,首先,百家乐肯定是每次摸一球个放进去,只是袋子里的球和你的数学模型一定要配合。
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举个例子,如果你是打庄闲的,袋子里永远只有两个球,每次摸完一个之后要放回去,然后再摸。这个概念是不容置疑的。
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" H m% u1 w. u- x0 Q第二,因为大数法则和算牌对百家乐的无效性,牌盒内所剩下多少牌,对庄闲的比例不会发生任何的变化* U: d& p3 d# r6 y% y7 ~5 @
0 P; ~8 }1 r% g, ]: @第三,凯利公式的问题在于:形而上学。$ V: \. }5 r+ x% r. e
9 e, C8 B1 }7 B1 s首先主观假设了一个不成立的底部,玩久了一定会遇到被爆仓的概念,当然任何一种模型都会有爆仓的可能,只是单纯的凯利更容易爆仓而已。研究的方向是多维+赢进补偿,玩过Diablo3就知道在Mp8的难度下,打到钥匙的可能性是80%。
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3 y8 Y8 C* I. Y- H* ~7 G事实上,你玩的时候,基本上每次都能打到。
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因此,百家乐连赢概率和连赢策略,对于不同的玩家有不同的理解,如何找到适合于自己的玩法和制胜之道,是每个玩家都需要积累实战经验去摸索的。
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